iBet uBet web content aggregator. Adding the entire web to your favor.
iBet uBet web content aggregator. Adding the entire web to your favor.



Link to original content: http://en.m.wikipedia.org/wiki/Green's_theorem
Green's theorem - Wikipedia

In vector calculus, Green's theorem relates a line integral around a simple closed curve C to a double integral over the plane region D (surface in ) bounded by C. It is the two-dimensional special case of Stokes' theorem (surface in ). In one dimension, it is equivalent to the fundamental theorem of calculus. In three dimensions, it is equivalent to the divergence theorem.

Theorem

edit

Let C be a positively oriented, piecewise smooth, simple closed curve in a plane, and let D be the region bounded by C. If L and M are functions of (x, y) defined on an open region containing D and have continuous partial derivatives there, then

 

where the path of integration along C is counterclockwise.[1][2]

Application

edit

In physics, Green's theorem finds many applications. One is solving two-dimensional flow integrals, stating that the sum of fluid outflowing from a volume is equal to the total outflow summed about an enclosing area. In plane geometry, and in particular, area surveying, Green's theorem can be used to determine the area and centroid of plane figures solely by integrating over the perimeter.

Proof when D is a simple region

edit
 
If D is a simple type of region with its boundary consisting of the curves C1, C2, C3, C4, half of Green's theorem can be demonstrated.

The following is a proof of half of the theorem for the simplified area D, a type I region where C1 and C3 are curves connected by vertical lines (possibly of zero length). A similar proof exists for the other half of the theorem when D is a type II region where C2 and C4 are curves connected by horizontal lines (again, possibly of zero length). Putting these two parts together, the theorem is thus proven for regions of type III (defined as regions which are both type I and type II). The general case can then be deduced from this special case by decomposing D into a set of type III regions.

If it can be shown that

  (1)

and

  (2)

are true, then Green's theorem follows immediately for the region D. We can prove (1) easily for regions of type I, and (2) for regions of type II. Green's theorem then follows for regions of type III.

Assume region D is a type I region and can thus be characterized, as pictured on the right, by   where g1 and g2 are continuous functions on [a, b]. Compute the double integral in (1):

  (3)

Now compute the line integral in (1). C can be rewritten as the union of four curves: C1, C2, C3, C4.

With C1, use the parametric equations: x = x, y = g1(x), axb. Then  

With C3, use the parametric equations: x = x, y = g2(x), axb. Then  

The integral over C3 is negated because it goes in the negative direction from b to a, as C is oriented positively (anticlockwise). On C2 and C4, x remains constant, meaning  

Therefore,

  (4)

Combining (3) with (4), we get (1) for regions of type I. A similar treatment yields (2) for regions of type II. Putting the two together, we get the result for regions of type III.

Proof for rectifiable Jordan curves

edit

We are going to prove the following

Theorem — Let   be a rectifiable, positively oriented Jordan curve in   and let   denote its inner region. Suppose that   are continuous functions with the property that   has second partial derivative at every point of  ,   has first partial derivative at every point of   and that the functions   are Riemann-integrable over  . Then  

We need the following lemmas whose proofs can be found in:[3]

Lemma 1 (Decomposition Lemma) — Assume   is a rectifiable, positively oriented Jordan curve in the plane and let   be its inner region. For every positive real  , let   denote the collection of squares in the plane bounded by the lines  , where   runs through the set of integers. Then, for this  , there exists a decomposition of   into a finite number of non-overlapping subregions in such a manner that

  1. Each one of the subregions contained in  , say  , is a square from  .
  2. Each one of the remaining subregions, say  , has as boundary a rectifiable Jordan curve formed by a finite number of arcs of   and parts of the sides of some square from  .
  3. Each one of the border regions   can be enclosed in a square of edge-length  .
  4. If   is the positively oriented boundary curve of  , then  
  5. The number   of border regions is no greater than  , where   is the length of  .

Lemma 2 — Let   be a rectifiable curve in the plane and let   be the set of points in the plane whose distance from (the range of)   is at most  . The outer Jordan content of this set satisfies  .

Lemma 3 — Let   be a rectifiable curve in   and let   be a continuous function. Then   and   where   is the oscillation of   on the range of  .

Now we are in position to prove the theorem:

Proof of Theorem. Let   be an arbitrary positive real number. By continuity of  ,   and compactness of  , given  , there exists   such that whenever two points of   are less than   apart, their images under   are less than   apart. For this  , consider the decomposition given by the previous Lemma. We have  

Put  .

For each  , the curve   is a positively oriented square, for which Green's formula holds. Hence  

Every point of a border region is at a distance no greater than   from  . Thus, if   is the union of all border regions, then  ; hence  , by Lemma 2. Notice that   This yields  

We may as well choose   so that the RHS of the last inequality is  

The remark in the beginning of this proof implies that the oscillations of   and   on every border region is at most  . We have  

By Lemma 1(iii),  

Combining these, we finally get   for some  . Since this is true for every  , we are done.

Validity under different hypotheses

edit

The hypothesis of the last theorem are not the only ones under which Green's formula is true. Another common set of conditions is the following:

The functions   are still assumed to be continuous. However, we now require them to be Fréchet-differentiable at every point of  . This implies the existence of all directional derivatives, in particular  , where, as usual,   is the canonical ordered basis of  . In addition, we require the function   to be Riemann-integrable over  .

As a corollary of this, we get the Cauchy Integral Theorem for rectifiable Jordan curves:

Theorem (Cauchy) — If   is a rectifiable Jordan curve in   and if   is a continuous mapping holomorphic throughout the inner region of  , then   the integral being a complex contour integral.

Proof

We regard the complex plane as  . Now, define   to be such that   These functions are clearly continuous. It is well known that   and   are Fréchet-differentiable and that they satisfy the Cauchy-Riemann equations:  .

Now, analyzing the sums used to define the complex contour integral in question, it is easy to realize that   the integrals on the RHS being usual line integrals. These remarks allow us to apply Green's Theorem to each one of these line integrals, finishing the proof.

Multiply-connected regions

edit

Theorem. Let   be positively oriented rectifiable Jordan curves in   satisfying   where   is the inner region of  . Let  

Suppose   and   are continuous functions whose restriction to   is Fréchet-differentiable. If the function   is Riemann-integrable over  , then  

Relationship to Stokes' theorem

edit

Green's theorem is a special case of the Kelvin–Stokes theorem, when applied to a region in the  -plane.

We can augment the two-dimensional field into a three-dimensional field with a z component that is always 0. Write F for the vector-valued function  . Start with the left side of Green's theorem:  

The Kelvin–Stokes theorem:  

The surface   is just the region in the plane  , with the unit normal   defined (by convention) to have a positive z component in order to match the "positive orientation" definitions for both theorems.

The expression inside the integral becomes  

Thus we get the right side of Green's theorem  

Green's theorem is also a straightforward result of the general Stokes' theorem using differential forms and exterior derivatives:  

Relationship to the divergence theorem

edit

Considering only two-dimensional vector fields, Green's theorem is equivalent to the two-dimensional version of the divergence theorem:

 

where   is the divergence on the two-dimensional vector field  , and   is the outward-pointing unit normal vector on the boundary.

To see this, consider the unit normal   in the right side of the equation. Since in Green's theorem   is a vector pointing tangential along the curve, and the curve C is the positively oriented (i.e. anticlockwise) curve along the boundary, an outward normal would be a vector which points 90° to the right of this; one choice would be  . The length of this vector is   So  

Start with the left side of Green's theorem:   Applying the two-dimensional divergence theorem with  , we get the right side of Green's theorem:  

Area calculation

edit

Green's theorem can be used to compute area by line integral.[4] The area of a planar region   is given by  

Choose   and   such that  , the area is given by  

Possible formulas for the area of   include[4]  

History

edit

It is named after George Green, who stated a similar result in an 1828 paper titled An Essay on the Application of Mathematical Analysis to the Theories of Electricity and Magnetism. In 1846, Augustin-Louis Cauchy published a paper stating Green's theorem as the penultimate sentence. This is in fact the first printed version of Green's theorem in the form appearing in modern textbooks. George Green, An Essay on the Application of Mathematical Analysis to the Theories of Electricity and Magnetism (Nottingham, England: T. Wheelhouse, 1828). Green did not actually derive the form of "Green's theorem" which appears in this article; rather, he derived a form of the "divergence theorem", which appears on pages 10–12 of his Essay.
In 1846, the form of "Green's theorem" which appears in this article was first published, without proof, in an article by Augustin Cauchy: A. Cauchy (1846) "Sur les intégrales qui s'étendent à tous les points d'une courbe fermée" (On integrals that extend over all of the points of a closed curve), Comptes rendus, 23: 251–255. (The equation appears at the bottom of page 254, where (S) denotes the line integral of a function k along the curve s that encloses the area S.)
A proof of the theorem was finally provided in 1851 by Bernhard Riemann in his inaugural dissertation: Bernhard Riemann (1851) Grundlagen für eine allgemeine Theorie der Functionen einer veränderlichen complexen Grösse (Basis for a general theory of functions of a variable complex quantity), (Göttingen, (Germany): Adalbert Rente, 1867); see pages 8–9.</ref>[5]

See also

edit
  • Planimeter – Tool for measuring area
  • Method of image charges – A method used in electrostatics that takes advantage of the uniqueness theorem (derived from Green's theorem)
  • Shoelace formula – A special case of Green's theorem for simple polygons
  • Desmos - A web based graphing calculator

References

edit
  1. ^ Riley, Kenneth F.; Hobson, Michael P.; Bence, Stephen J. (2010). Mathematical methods for physics and engineering (3rd ed.). Cambridge: Cambridge University Press. ISBN 978-0-521-86153-3.
  2. ^ Lipschutz, Seymour; Spiegel, Murray R. (2009). Vector analysis and an introduction to tensor analysis. Schaum's outline series (2nd ed.). New York: McGraw Hill Education. ISBN 978-0-07-161545-7. OCLC 244060713.
  3. ^ Apostol, Tom (1960). Mathematical Analysis. Reading, Massachusetts, U.S.A.: Addison-Wesley. OCLC 6699164.
  4. ^ a b Stewart, James (1999). Calculus. GWO - A Gary W. Ostedt book (4. ed.). Pacific Grove, Calif. London: Brooks/Cole. ISBN 978-0-534-35949-2.
  5. ^ Katz, Victor J. (2009). "22.3.3: Complex Functions and Line Integrals". A history of mathematics: an introduction (PDF) (3. ed.). Boston, Mass. Munich: Addison-Wesley. pp. 801–5. ISBN 978-0-321-38700-4.

Further reading

edit
edit