iBet uBet web content aggregator. Adding the entire web to your favor.
iBet uBet web content aggregator. Adding the entire web to your favor.



Link to original content: http://en.m.wikipedia.org/wiki/Cauchy_integral_theorem
Cauchy's integral theorem - Wikipedia

Cauchy's integral theorem

(Redirected from Cauchy integral theorem)

In mathematics, the Cauchy integral theorem (also known as the Cauchy–Goursat theorem) in complex analysis, named after Augustin-Louis Cauchy (and Édouard Goursat), is an important statement about line integrals for holomorphic functions in the complex plane. Essentially, it says that if is holomorphic in a simply connected domain Ω, then for any simply closed contour in Ω, that contour integral is zero.

Statement

edit

Fundamental theorem for complex line integrals

edit

If f(z) is a holomorphic function on an open region U, and   is a curve in U from   to   then,  

Also, when f(z) has a single-valued antiderivative in an open region U, then the path integral   is path independent for all paths in U.

Formulation on simply connected regions

edit

Let   be a simply connected open set, and let   be a holomorphic function. Let   be a smooth closed curve. Then:   (The condition that   be simply connected means that   has no "holes", or in other words, that the fundamental group of   is trivial.)

General formulation

edit

Let   be an open set, and let   be a holomorphic function. Let   be a smooth closed curve. If   is homotopic to a constant curve, then:   (Recall that a curve is homotopic to a constant curve if there exists a smooth homotopy (within  ) from the curve to the constant curve. Intuitively, this means that one can shrink the curve into a point without exiting the space.) The first version is a special case of this because on a simply connected set, every closed curve is homotopic to a constant curve.

Main example

edit

In both cases, it is important to remember that the curve   does not surround any "holes" in the domain, or else the theorem does not apply. A famous example is the following curve:   which traces out the unit circle. Here the following integral:   is nonzero. The Cauchy integral theorem does not apply here since   is not defined at  . Intuitively,   surrounds a "hole" in the domain of  , so   cannot be shrunk to a point without exiting the space. Thus, the theorem does not apply.

Discussion

edit

As Édouard Goursat showed, Cauchy's integral theorem can be proven assuming only that the complex derivative   exists everywhere in  . This is significant because one can then prove Cauchy's integral formula for these functions, and from that deduce these functions are infinitely differentiable.

The condition that   be simply connected means that   has no "holes" or, in homotopy terms, that the fundamental group of   is trivial; for instance, every open disk  , for  , qualifies. The condition is crucial; consider   which traces out the unit circle, and then the path integral   is nonzero; the Cauchy integral theorem does not apply here since   is not defined (and is certainly not holomorphic) at  .

One important consequence of the theorem is that path integrals of holomorphic functions on simply connected domains can be computed in a manner familiar from the fundamental theorem of calculus: let   be a simply connected open subset of  , let   be a holomorphic function, and let   be a piecewise continuously differentiable path in   with start point   and end point  . If   is a complex antiderivative of  , then  

The Cauchy integral theorem is valid with a weaker hypothesis than given above, e.g. given  , a simply connected open subset of  , we can weaken the assumptions to   being holomorphic on   and continuous on   and   a rectifiable simple loop in  .[1]

The Cauchy integral theorem leads to Cauchy's integral formula and the residue theorem.

Proof

edit

If one assumes that the partial derivatives of a holomorphic function are continuous, the Cauchy integral theorem can be proven as a direct consequence of Green's theorem and the fact that the real and imaginary parts of   must satisfy the Cauchy–Riemann equations in the region bounded by  , and moreover in the open neighborhood U of this region. Cauchy provided this proof, but it was later proven by Goursat without requiring techniques from vector calculus, or the continuity of partial derivatives.

We can break the integrand  , as well as the differential   into their real and imaginary components:

   

In this case we have  

By Green's theorem, we may then replace the integrals around the closed contour   with an area integral throughout the domain   that is enclosed by   as follows:

   

But as the real and imaginary parts of a function holomorphic in the domain  ,   and   must satisfy the Cauchy–Riemann equations there:    

We therefore find that both integrands (and hence their integrals) are zero

   

This gives the desired result  

See also

edit

References

edit
  1. ^ Walsh, J. L. (1933-05-01). "The Cauchy-Goursat Theorem for Rectifiable Jordan Curves". Proceedings of the National Academy of Sciences. 19 (5): 540–541. doi:10.1073/pnas.19.5.540. ISSN 0027-8424. PMC 1086062. PMID 16587781.
edit