The 1990 Rhode Island United States Senate election was held on November 6, 1990, to select the U.S. Senator from the state of Rhode Island. Democratic U.S. Senator Claiborne Pell decided to seek re-election and defeated Republican Representative Claudine Schneider in a landslide.[1]
| |||||||||||||||||
| |||||||||||||||||
Pell: 50–60% 60–70% 70–80% Schneider: 50–60% | |||||||||||||||||
|
Candidates
editDemocrat
edit- Claiborne Pell, incumbent U.S. Senator
Republican
edit- Claudine Schneider, U.S. Representative
Results
editParty | Candidate | Votes | % | ±% | |
---|---|---|---|---|---|
Democratic | Claiborne Pell (Incumbent) | 225,105 | 61.83% | −10.83% | |
Republican | Claudine Schneider | 138,947 | 38.17% | +10.83% | |
Majority | 86,158 | 23.67% | −21.65% | ||
Turnout | 364,062 | ||||
Democratic hold | Swing |